What is ((x^2-4x+3))/((x^2-6x+9)) ?

The solution to ((x^2-4x+3))/((x^2-6x+9)) is (x-1)/(x-3)

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simplify ((x^2-4x+3))/((x^2-6x+9))

simplify

\frac{( x ^{2} - 4 x + 3 )}{( x ^{2} - 6 x + 9 )}

\frac{x - 1}{x - 3}

Solution steps

\frac{x ^{2} - 4 x + 3}{x ^{2} - 6 x + 9}

Factor

x^{2} - 4 x + 3 : (x - 1) (x - 3)

= \frac{( x - 1 ) ( x - 3 )}{x ^{2} - 6 x + 9}

Factor

x^{2} - 6 x + 9 : (x - 3)^{2}

= \frac{( x - 1 ) ( x - 3 )}{( x - 3 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x - 3)^{2} = (x - 3) (x - 3)

= \frac{( x - 1 ) ( x - 3 )}{( x - 3 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{x - 1}{x - 3}

(8 x^{5} \cdot y^{3})^{2}

(3 x^{- 3} y^{3})^{- 2}

4 x^{2} + 32 x y + 4 y^{2}

(2 x - 2 y + 2)^{3}

2 x^{3} + 6 x^{2} + 2 x^{2} + 5 x - 100

What is ((x^2-4x+3))/((x^2-6x+9)) ?
The solution to ((x^2-4x+3))/((x^2-6x+9)) is (x-1)/(x-3)