What is factor 5y^3-4y^2+10y-8 ?

The solution to factor 5y^3-4y^2+10y-8 is (5y-4)(y^2+2)

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factor 5y^3-4y^2+10y-8

factor

5 y^{3} - 4 y^{2} + 10 y - 8

(5 y - 4) (y^{2} + 2)

Solution steps

5 y^{3} - 4 y^{2} + 10 y - 8

= (5 y^{3} - 4 y^{2}) + (10 y - 8)

Factor out

y^{2}

from

5 y^{3} - 4 y^{2} : y^{2} (5 y - 4)

Factor out

2

from

10 y - 8 : 2 (5 y - 4)

= y^{2} (5 y - 4) + 2 (5 y - 4)

Factor out common term

5 y - 4

= (5 y - 4) (y^{2} + 2)

l^{+} [\frac{s}{( s ^{2} + s - 2 )}]

^{'} arcsin \frac{( 1 )}{( 1 x ^{2} )}^{'}

f (x) + f (5)

8.8 (a + b) \frac{2}{c} - 0 \cdot 5 + \frac{29}{( 9 + y )} (a + b) \cdot (\frac{1}{h})

7 (x + 2) \cdot (x - 7)^{3}

What is factor 5y^3-4y^2+10y-8 ?
The solution to factor 5y^3-4y^2+10y-8 is (5y-4)(y^2+2)