What is (5a^4b^3)(-2a^2b^5)(4a^2b) ?

The solution to (5a^4b^3)(-2a^2b^5)(4a^2b) is -40a^8b^9

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simplify (5a^4b^3)(-2a^2b^5)(4a^2b)

simplify

(5 a^{4} b^{3}) (- 2 a^{2} b^{5}) (4 a^{2} b)

- 40 a^{8} b^{9}

Solution steps

(5 a^{4} b^{3}) (- 2 a^{2} b^{5}) (4 a^{2} b)

Apply rule:

a (- b) = - ab

(5 a^{4} b^{3}) (- 2 a^{2} b^{5}) = - 5 a^{4} b^{3} \cdot 2 a^{2} b^{5}

= - 5 a^{4} b^{3} \cdot 2 a^{2} b^{5} \cdot 4 a^{2} b

Multiply the numbers:

- 5 \cdot 2 \cdot 4 = - 40

= - 40 a^{4} b^{3} a^{2} b^{5} a^{2} b

Simplify

a^{4} a^{2} a^{2} : a^{8}

= - 40 a^{8} b^{3} b^{5} b

Simplify

b^{3} b^{5} b : b^{9}

= - 40 a^{8} b^{9}

(- 4 x^{4} \cdot 4 y^{3} \cdot z)^{2}

(\frac{( 16 w ^{8} )}{( y ^{20} )})^{\frac{- 3}{4}}

\frac{( 1 + \frac{a}{b} )}{( 1 + \frac{b}{a} )}

(\frac{9}{16} \frac{x ^{4}}{12}) + (\frac{9}{16} x - \frac{3}{9})

x^{'} - y (\frac{x}{y}) + a (y)^{2}

What is (5a^4b^3)(-2a^2b^5)(4a^2b) ?
The solution to (5a^4b^3)(-2a^2b^5)(4a^2b) is -40a^8b^9