What are the solutions to the equation 25x^2+1=0 ?

The solutions to the equation 25x^2+1=0 are x= 1/5 i,x=-1/5 i

Find the zeros of 25x^2+1=0

The zeros of 25x^2+1=0 are x= 1/5 i,x=-1/5 i

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25 x^{2} + 1 = 0

x = \frac{1}{5} i, x = - \frac{1}{5} i

Solution steps

25 x^{2} + 1 = 0

Move

1

to the right side

25 x^{2} = - 1

Divide both sides by

25

x^{2} = - \frac{1}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{25}, x = - - \frac{1}{25}

- \frac{1}{25} = \frac{1}{5} i

- - \frac{1}{25} = - \frac{1}{5} i

x = \frac{1}{5} i, x = - \frac{1}{5} i

\frac{x - 5}{3} < \frac{22}{5}

\frac{3}{\frac{2}{3}}

2 x^{2} - 200 = 0

2 w \geq - 10

3 x - 3

What are the solutions to the equation 25x^2+1=0 ?
The solutions to the equation 25x^2+1=0 are x= 1/5 i,x=-1/5 i
Find the zeros of 25x^2+1=0
The zeros of 25x^2+1=0 are x= 1/5 i,x=-1/5 i