What is ([((x+3))/((x-2))]}{[\frac{(1-x))/x ]} ?

The solution to ([((x+3))/((x-2))]}{[\frac{(1-x))/x ]} is ((x+3)x)/((x-2)(1-x))

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simplify ([((x+3))/((x-2))]}{[\frac{(1-x))/x ]}

simplify

\frac{[ \frac{( x + 3 )}{( x - 2 )} ]}{[ \frac{( 1 - x )}{x} ]}

\frac{( x + 3 ) x}{( x - 2 ) ( 1 - x )}

Solution steps

\frac{\frac{x + 3}{x - 2}}{\frac{1 - x}{x}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x + 3 ) x}{( x - 2 ) ( 1 - x )}

\frac{y ^{\frac{1}{3}}}{( ( y ^{- \frac{1}{2}} ) ( y ^{\frac{1}{4}} ) )}

x^{3} - 1000 y^{3}

sin^{- 5} (\frac{( 1 + x ^{2} )}{2})

8 r^{2} - 12 x^{2}

x^{7} \cdot y^{7} - x y

What is ([((x+3))/((x-2))]}{[\frac{(1-x))/x ]} ?
The solution to ([((x+3))/((x-2))]}{[\frac{(1-x))/x ]} is ((x+3)x)/((x-2)(1-x))