What is (3x^{-7}*y^7*z^{-5})^{-1} ?

The solution to (3x^{-7}*y^7*z^{-5})^{-1} is (x^7z^5)/(3y^7)

Popular >

simplify (3x^{-7}y^7z^{-5})^{-1}

simplify

(3 x^{- 7} \cdot y^{7} \cdot z^{- 5})^{- 1}

\frac{x ^{7} z ^{5}}{3 y ^{7}}

Solution steps

(3 x^{- 7} y^{7} z^{- 5})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(3 x^{- 7} y^{7} z^{- 5})^{- 1} = \frac{1}{3 x ^{- 7} y ^{7} z ^{- 5}}

= \frac{1}{3 x ^{- 7} y ^{7} z ^{- 5}}

Multiply

3 x^{- 7} y^{7} z^{- 5} : \frac{3 y ^{7}}{x ^{7} z ^{5}}

= \frac{1}{\frac{3 y ^{7}}{x ^{7} z ^{5}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{7} z ^{5}}{3 y ^{7}}

25 x^{4} y^{4} - 91 x^{2} y^{4} - 36 y^{4}

(\frac{x + 1}{x}) (\frac{x - 1}{x}) (\frac{x ^{2} + 1}{( x ^{2} )})

\frac{( m ^{3} - m ^{4} )}{( m ^{2} - 8 m + 7 )}

x^{4} y^{3} + x^{5} y^{5}

x^{3} + 3 x + 3 x^{2} + 1

What is (3x^{-7}*y^7*z^{-5})^{-1} ?
The solution to (3x^{-7}*y^7*z^{-5})^{-1} is (x^7z^5)/(3y^7)