What are the solutions to the equation m^2-25/2 m= 5/2 ?

The solutions to the equation m^2-25/2 m= 5/2 are m=(25+sqrt(665))/4 ,m=(25-sqrt(665))/4

Find the zeros of m^2-25/2 m= 5/2

The zeros of m^2-25/2 m= 5/2 are m=(25+sqrt(665))/4 ,m=(25-sqrt(665))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} - \frac{25}{2} m = \frac{5}{2}

m = \frac{25 + 665}{4}, m = \frac{25 - 665}{4}

Decimal Notation

m = 12.69689 \dots, m = - 0.19689 \dots

Solution steps

m^{2} - \frac{25}{2} m = \frac{5}{2}

Multiply both sides by

2

2 m^{2} - 25 m = 5

Move

5

to the left side

2 m^{2} - 25 m - 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 25)^{2} - 4 \cdot 2 (- 5) = 665

m_{1, 2} = \frac{- ( - 25 ) \pm 665}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 25 ) + 665}{2 \cdot 2}, m_{2} = \frac{- ( - 25 ) - 665}{2 \cdot 2}

m = \frac{- ( - 25 ) + 665}{2 \cdot 2} : \frac{25 + 665}{4}

m = \frac{- ( - 25 ) - 665}{2 \cdot 2} : \frac{25 - 665}{4}

The solutions to the quadratic equation are:

m = \frac{25 + 665}{4}, m = \frac{25 - 665}{4}

3 a^{- 5}

x^{3} + 5 x^{2} - x - 5 > 0

X^{2} + 7 X + 12 = 0

2 x^{2} + 2 x + 6

x + 2 \geq x - 3

What are the solutions to the equation m^2-25/2 m= 5/2 ?
The solutions to the equation m^2-25/2 m= 5/2 are m=(25+sqrt(665))/4 ,m=(25-sqrt(665))/4
Find the zeros of m^2-25/2 m= 5/2
The zeros of m^2-25/2 m= 5/2 are m=(25+sqrt(665))/4 ,m=(25-sqrt(665))/4