What is (15a^3b^4x^4)(3a^2b^2x^3)^{-1} ?

The solution to (15a^3b^4x^4)(3a^2b^2x^3)^{-1} is 5axb^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (15a^3b^4x^4)(3a^2b^2x^3)^{-1}

simplify

(15 a^{3} b^{4} x^{4}) (3 a^{2} b^{2} x^{3})^{- 1}

5 a x b^{2}

Solution steps

(15 a^{3} b^{4} x^{4}) (3 a^{2} b^{2} x^{3})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(3 a^{2} b^{2} x^{3})^{- 1} = \frac{1}{3 a ^{2} b ^{2} x ^{3}}

= 15 a^{3} b^{4} x^{4} \frac{1}{3 a ^{2} b ^{2} x ^{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{15 a ^{3} b ^{4} x ^{4} \cdot 1}{3 a ^{2} b ^{2} x ^{3}}

Multiply the numbers:

15 \cdot 1 = 15

= \frac{15 a ^{3} b ^{4} x ^{4}}{3 a ^{2} b ^{2} x ^{3}}

Factor the number:

15 = 3 \cdot 5

= \frac{3 \cdot 5 a ^{3} b ^{4} x ^{4}}{3 a ^{2} b ^{2} x ^{3}}

Cancel the common factor:

3

= \frac{5 a ^{3} b ^{4} x ^{4}}{a ^{2} b ^{2} x ^{3}}

Simplify

\frac{a ^{3}}{a ^{2}} : a

= \frac{5 a b ^{4} x ^{4}}{b ^{2} x ^{3}}

Simplify

\frac{b ^{4}}{b ^{2}} : b^{2}

= \frac{5 a b ^{2} x ^{4}}{x ^{3}}

Simplify

\frac{x ^{4}}{x ^{3}} : x

= 5 a b^{2} x

= 5 a x b^{2}

4 z^{2} + 23 z - 35

\frac{( 2 x )}{( 3 y - 3 x )} + \frac{( 3 y )}{( 5 x - 5 y )}

\frac{1}{( a ^{- 2} + b )}

a^{16} - b^{16}

x^{4} y^{2} + (7 + 5) x^{2} y + 35

What is (15a^3b^4x^4)(3a^2b^2x^3)^{-1} ?
The solution to (15a^3b^4x^4)(3a^2b^2x^3)^{-1} is 5axb^2