What is 1/((a^{-2)+b)} ?

The solution to 1/((a^{-2)+b)} is (a^2)/(ba^2+1)

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simplify 1/((a^{-2)+b)}

simplify

\frac{1}{( a ^{- 2} + b )}

\frac{a ^{2}}{b a ^{2} + 1}

Solution steps

\frac{1}{a ^{- 2} + b}

Simplify

a^{- 2} + b : \frac{b a ^{2} + 1}{a ^{2}}

= \frac{1}{\frac{b a ^{2} + 1}{a ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{a ^{2}}{b a ^{2} + 1}

a^{16} - b^{16}

x^{4} y^{2} + (7 + 5) x^{2} y + 35

d^{4} + 18 d^{2} + 81

\frac{1}{( 1 + x ^{a + b} )} + \frac{1}{( 1 + x ^{b - a} )}

(\frac{3}{x + 4 x}) (\frac{- 2 x - 7}{x})