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Popular >

simplify [(a^{-1})]^{-1}

Solution

simplify

[(a^{- 1})]^{- 1}

Solution

a

Solution steps

(a^{- 1})^{- 1}

Apply rule:

(a) = a

(a^{- 1}) = a^{- 1}

= (a^{- 1})^{- 1}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= a^{- 1 \cdot (- 1)}

- 1 \cdot (- 1) = 1

= a^{1}

Apply exponent rule:

a^{1} = a

= a

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Frequently Asked Questions (FAQ)

What is [(a^{-1})]^{-1} ?
The solution to [(a^{-1})]^{-1} is a