What is (a+b)^{-1}+(a-b)^{-1} ?

The solution to (a+b)^{-1}+(a-b)^{-1} is 1/(a+b)+1/(a-b)

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simplify (a+b)^{-1}+(a-b)^{-1}

simplify

(a + b)^{- 1} + (a - b)^{- 1}

\frac{1}{a + b} + \frac{1}{a - b}

Solution steps

(a + b)^{- 1} + (a - b)^{- 1}

(a + b)^{- 1} = \frac{1}{a + b}

(a - b)^{- 1} = \frac{1}{a - b}

= \frac{1}{a + b} + \frac{1}{a - b}

x^{2} + \frac{\frac{x ^{5}}{2}}{\frac{x ^{- 1}}{2}}

\frac{1}{8} p^{3} + \frac{1}{27} q^{3}

2 a (a + 3)

\frac{( ( 3 a ^{7} ) ( 2 a ^{5} ) )}{( 24 a ^{15} )}

(d) - 4. 2^{n} - \frac{( - 1 )}{4} \cdot n^{2} - \frac{1}{5} \cdot n + \frac{1}{8}

What is (a+b)^{-1}+(a-b)^{-1} ?
The solution to (a+b)^{-1}+(a-b)^{-1} is 1/(a+b)+1/(a-b)