What is ((2h^3k^2-6h^4k^5))/((2h^2k)) ?

The solution to ((2h^3k^2-6h^4k^5))/((2h^2k)) is hk(1-3hk^3)

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simplify ((2h^3k^2-6h^4k^5))/((2h^2k))

simplify

\frac{( 2 h ^{3} k ^{2} - 6 h ^{4} k ^{5} )}{( 2 h ^{2} k )}

hk (1 - 3 h k^{3})

Solution steps

\frac{2 h ^{3} k ^{2} - 6 h ^{4} k ^{5}}{2 h ^{2} k}

Factor

2 h^{3} k^{2} - 6 h^{4} k^{5} : 2 h^{3} k^{2} (1 - 3 h k^{3})

= \frac{2 h ^{3} k ^{2} ( 1 - 3 h k ^{3} )}{2 h ^{2} k}

Cancel the common factor:

2

= \frac{h ^{3} k ^{2} ( 1 - 3 h k ^{3} )}{h ^{2} k}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

h^{3} = h^{2} h

= \frac{h ^{2} h k ^{2} ( 1 - 3 h k ^{3} )}{h ^{2} k}

Cancel the common factor:

h^{2}

= \frac{h k ^{2} ( 1 - 3 h k ^{3} )}{k}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

k^{2} = kk

= \frac{hkk ( 1 - 3 h k ^{3} )}{k}

Cancel the common factor:

k

= hk (1 - 3 h k^{3})

\frac{( 2 x ^{2} - x )}{x}

l [t^{4}]

\frac{( 8 x 1 0 ^{3} )}{( 2 x 1 0 ^{5} )}

(r^{- 7})^{6}

1.6 x^{2} - 4 \frac{y ^{2}}{2} y + 0.4 x

What is ((2h^3k^2-6h^4k^5))/((2h^2k)) ?
The solution to ((2h^3k^2-6h^4k^5))/((2h^2k)) is hk(1-3hk^3)