What is factor a^4-81b^4 ?

The solution to factor a^4-81b^4 is (a^2+9b^2)(a+3b)(a-3b)

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factor a^4-81b^4

factor

a^{4} - 81 b^{4}

(a^{2} + 9 b^{2}) (a + 3 b) (a - 3 b)

Solution steps

a^{4} - 81 b^{4}

a^{4} = (a^{2})^{2}

81 b^{4} = (9 b^{2})^{2}

= (a^{2})^{2} - (9 b^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a^{2})^{2} - (9 b^{2})^{2} = (a^{2} + 9 b^{2}) (a^{2} - 9 b^{2})

= (a^{2} + 9 b^{2}) (a^{2} - 9 b^{2})

Factor

a^{2} - 9 b^{2} : (a + 3 b) (a - 3 b)

= (a^{2} + 9 b^{2}) (a + 3 b) (a - 3 b)

(arcsin (x))^{32} 1 - x^{2}

\frac{3 x - 9}{9 - 9 x}

3^{2 + l o g_{3} (4)} j

\frac{( 4 y ^{2} - 16 )}{( y ^{2} + 3 y + 2 )}

- 0.4 (- 6 g - 6 h) - 2 h - 0.2 (- 5 h + 3 g)

What is factor a^4-81b^4 ?
The solution to factor a^4-81b^4 is (a^2+9b^2)(a+3b)(a-3b)