What is ((2n-3)!)/((2n-1)!) ?

The solution to ((2n-3)!)/((2n-1)!) is 1/((2n-2)(2n-1))

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simplify ((2n-3)!)/((2n-1)!)

simplify

\frac{( 2 n - 3 ) !}{( 2 n - 1 ) !}

\frac{1}{( 2 n - 2 ) ( 2 n - 1 )}

Solution steps

\frac{( 2 n - 3 ) !}{( 2 n - 1 ) !}

Cancel the factorials:

\frac{n !}{( n + m ) !} = \frac{1}{( n + 1 ) \cdot ( n + 2 ) \dots ( n + m )}

\frac{( 2 n - 3 ) !}{( 2 n - 1 ) !} = \frac{1}{( 2 n - 2 ) ( 2 n - 1 )}

= \frac{1}{( 2 n - 2 ) ( 2 n - 1 )}

x^{3} n + x^{- 3} n

(x^{2} - 4 y^{2})^{3}

\frac{( 3 a )}{( 16 - 4 a )} + \frac{3}{( a - 4 )}

2^{3 n}

[\frac{1}{2 \cdot x + y}]^{2}

What is ((2n-3)!)/((2n-1)!) ?
The solution to ((2n-3)!)/((2n-1)!) is 1/((2n-2)(2n-1))