What is factor 16u^2+40u+25-9v^2 ?

The solution to factor 16u^2+40u+25-9v^2 is (4u+5+3v)(4u+5-3v)

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factor 16u^2+40u+25-9v^2

factor

16 u^{2} + 40 u + 25 - 9 v^{2}

(4 u + 5 + 3 v) (4 u + 5 - 3 v)

Solution steps

16 u^{2} + 40 u + 25 - 9 v^{2}

Factor

16 u^{2} + 40 u + 25 : (4 u + 5)^{2}

= (4 u + 5)^{2} - 9 v^{2}

Simplify

9 v^{2} : (3 v)^{2}

= (4 u + 5)^{2} - (3 v)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 u + 5)^{2} - (3 v)^{2} = ((4 u + 5) + 3 v) ((4 u + 5) - 3 v)

= ((4 u + 5) + 3 v) ((4 u + 5) - 3 v)

Apply rule:

(a) = a

(4 u + 5) = 4 u + 5

= (4 u + 5 + 3 v) (4 u + 5 - 3 v)

3 = 0.2 m - 7

0.64 \cdot 5 + \frac{1}{8} \cdot 1600

(x - 4) (x + 2) (3 - x) > 0

5 x^{2} - 21 x + 4 = 0

\frac{3}{2} y = \frac{5}{12}

What is factor 16u^2+40u+25-9v^2 ?
The solution to factor 16u^2+40u+25-9v^2 is (4u+5+3v)(4u+5-3v)