What is the answer to solvefor a,f=3a-3b+c-(4a-5b-c) ?

The answer to solvefor a,f=3a-3b+c-(4a-5b-c) is a=2c+2b-f

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solvefor a,f=3a-3b+c-(4a-5b-c)

solve for

a, f = 3 a - 3 b + c - (4 a - 5 b - c)

a = 2 c + 2 b - f

Solution steps

f = 3 a - 3 b + c - (4 a - 5 b - c)

Switch sides

3 a - 3 b + c - (4 a - 5 b - c) = f

Move

3 b

to the right side

3 a + c - (4 a - 5 b - c) = f + 3 b

Move

c

to the right side

3 a - (4 a - 5 b - c) = f + 3 b - c

Expand

3 a - (4 a - 5 b - c) : - a + 5 b + c

- a + 5 b + c = f + 3 b - c

Move

5 b

to the right side

- a + c = - 2 b - c + f

Move

c

to the right side

- a = - 2 c - 2 b + f

Divide both sides by

- 1

a = 2 c + 2 b - f

x, 4 x = - y + 16

\frac{( 4 x + 1 )}{8} = - 4 \frac{x}{10} - 2 \frac{x}{8}

x, x - 7 = y + 7

z = \frac{( 2 - - 25 )}{( 1 - - 36 )}

7 x + 5 = 10

What is the answer to solvefor a,f=3a-3b+c-(4a-5b-c) ?
The answer to solvefor a,f=3a-3b+c-(4a-5b-c) is a=2c+2b-f