What is the answer to solvefor x,p^3-p(y+3)+x=0 ?

The answer to solvefor x,p^3-p(y+3)+x=0 is x=-p^3+p(y+3)

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solvefor x,p^3-p(y+3)+x=0

solve for

x, p^{3} - p (y + 3) + x = 0

x = - p^{3} + p (y + 3)

Solution steps

p^{3} - p (y + 3) + x = 0

Move

p^{3}

to the right side

- p (y + 3) + x = - p^{3}

Move

p (y + 3)

to the right side

x = - p^{3} + p (y + 3)

0.3 (6 + x) = 0.4 (8 - x)

x, g = \frac{2}{5} f - 2

x, p^{2} + q^{2} = x + y

n, f = 2 f (n - 1)

x, 3 x + 4 y = - 10

What is the answer to solvefor x,p^3-p(y+3)+x=0 ?
The answer to solvefor x,p^3-p(y+3)+x=0 is x=-p^3+p(y+3)