What are the solutions to the equation 72*(2-x-2)^2= x/(18) ?

The solutions to the equation 72*(2-x-2)^2= x/(18) are x= 1/1296 ,x=0

Find the zeros of 72*(2-x-2)^2= x/(18)

The zeros of 72*(2-x-2)^2= x/(18) are x= 1/1296 ,x=0

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72 \cdot (2 - x - 2)^{2} = \frac{x}{18}

x = \frac{1}{1296}, x = 0

Decimal Notation

x = 0.00077 \dots, x = 0

Solution steps

72 (2 - x - 2)^{2} = \frac{x}{18}

Multiply both sides by

18

1296 x^{2} = x

Move

x

to the left side

1296 x^{2} - x = 0

Divide both sides by

1296

\frac{1296 x ^{2}}{1296} - \frac{x}{1296} = \frac{0}{1296}

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - \frac{x}{1296} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - \frac{1}{1296} ) \pm ( - \frac{1}{1296} ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- \frac{1}{1296})^{2} - 4 \cdot 1 \cdot 0 = \frac{1}{1296}

x_{1, 2} = \frac{- ( - \frac{1}{1296} ) \pm \frac{1}{1296}}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - \frac{1}{1296} ) + \frac{1}{1296}}{2 \cdot 1}, x_{2} = \frac{- ( - \frac{1}{1296} ) - \frac{1}{1296}}{2 \cdot 1}

x = \frac{- ( - \frac{1}{1296} ) + \frac{1}{1296}}{2 \cdot 1} : \frac{1}{1296}

x = \frac{- ( - \frac{1}{1296} ) - \frac{1}{1296}}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = \frac{1}{1296}, x = 0

105 \cdot \frac{π}{180}

4 - x^{2} = 2 - x

980 \cdot \frac{4}{7}

\frac{1200}{4}

(5 + 3) (5 - 3)

What are the solutions to the equation 72*(2-x-2)^2= x/(18) ?
The solutions to the equation 72*(2-x-2)^2= x/(18) are x= 1/1296 ,x=0
Find the zeros of 72*(2-x-2)^2= x/(18)
The zeros of 72*(2-x-2)^2= x/(18) are x= 1/1296 ,x=0