What is the answer to x/2+2/3 = x/3+1-1/2*(1-((x+1))/3) ?

The answer to x/2+2/3 = x/3+1-1/2*(1-((x+1))/3) is True for all x

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x/2+2/3 = x/3+1-1/2*(1-((x+1))/3)

\frac{x}{2} + \frac{2}{3} = \frac{x}{3} + 1 - \frac{1}{2} \cdot (1 - \frac{( x + 1 )}{3})

True for all x

Solution steps

\frac{x}{2} + \frac{2}{3} = \frac{x}{3} + 1 - \frac{1}{2} (1 - \frac{( x + 1 )}{3})

\frac{1}{2} (1 - \frac{x + 1}{3}) = \frac{1 - \frac{x + 1}{3}}{2}

\frac{x}{2} + \frac{2}{3} = \frac{x}{3} + 1 - \frac{1 - \frac{x + 1}{3}}{2}

Multiply by LCM

3 x + 4 = 2 x + 6 - (3 - (x + 1))

Expand

2 x + 6 - (3 - (x + 1)) : 3 x + 4

3 x + 4 = 3 x + 4

Move

4

to the right side

3 x = 3 x

Move

3 x

to the left side

0 = 0

Both sides are equal

True for all x

z, f = 3!

(5 x - 1)^{2} - 7 x (3 x - 2) = (2 x - 3)^{2}

x, 2 x - 5 y = 2

0.9 x + 0.5 = - 0.01 x

a, a \cdot x^{2} + 3 x - 33 = 3 x

What is the answer to x/2+2/3 = x/3+1-1/2*(1-((x+1))/3) ?
The answer to x/2+2/3 = x/3+1-1/2*(1-((x+1))/3) is True for all x
Solve for x: x/2+2/3 = x/3+1-1/2*(1-((x+1))/3)
The solution is True for all x