What is the answer to ((10x)}{11}-\frac{(3x))/2 =33x-x/2+7 ?

The answer to ((10x)}{11}-\frac{(3x))/2 =33x-x/2+7 is x=-11/52

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((10x)}{11}-\frac{(3x))/2 =33x-x/2+7

\frac{( 10 x )}{11} - \frac{( 3 x )}{2} = 33 x - \frac{x}{2} + 7

x = - \frac{11}{52}

Decimal Notation

x = - 0.21153 \dots

Solution steps

\frac{( 10 x )}{11} - \frac{( 3 x )}{2} = 33 x - \frac{x}{2} + 7

\frac{10 x}{11} - \frac{3 x}{2} = 33 x - \frac{x}{2} + 7

Multiply by LCM

- 13 x = 715 x + 154

Move

715 x

to the left side

- 728 x = 154

Divide both sides by

- 728

x = - \frac{11}{52}

n, n (x) = 2 x^{2} + 4 - 6 x - 2 x^{3} + x^{2} + 1

f, - f \cdot (x) = (4 - x)^{3}

a, a + b - 7 = 10

z = \frac{( 2 - 2 i )}{( 2 + 2 i )}

x, 5 x + 4 y = 42

What is the answer to ((10x)}{11}-\frac{(3x))/2 =33x-x/2+7 ?
The answer to ((10x)}{11}-\frac{(3x))/2 =33x-x/2+7 is x=-11/52
Solve for x: ((10x)}{11}-\frac{(3x))/2 =33x-x/2+7
The solution is x=-11/52