What is the answer to solvefor y,2x+(y-4/(x^2))2=1 ?

The answer to solvefor y,2x+(y-4/(x^2))2=1 is y=(1-2x)/2+4/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor y,2x+(y-4/(x^2))2=1

solve for

y, 2 x + (y - \frac{4}{x ^{2}}) 2 = 1

y = \frac{1 - 2 x}{2} + \frac{4}{x ^{2}}

Solution steps

2 x + (y - \frac{4}{x ^{2}}) \cdot 2 = 1

Move

2 x

to the right side

(y - \frac{4}{x ^{2}}) \cdot 2 = 1 - 2 x

Divide both sides by

2

y - \frac{4}{x ^{2}} = \frac{1 - 2 x}{2}

Move

\frac{4}{x ^{2}}

to the right side

y = \frac{1 - 2 x}{2} + \frac{4}{x ^{2}}

(y^{1})^{1} + y^{1} + y = 0

x, y - 2 = - 4 (x - 3)

x, \frac{x}{3} + \frac{y}{5} = 7

0.2 x + 2.1 = 5.3 - 0.8 x

0.3 (6 y - 4) = 0.09 (3 y + 5)

What is the answer to solvefor y,2x+(y-4/(x^2))2=1 ?
The answer to solvefor y,2x+(y-4/(x^2))2=1 is y=(1-2x)/2+4/(x^2)