What is the answer to solvefor x,3y-2x+12=0 ?

The answer to solvefor x,3y-2x+12=0 is x=-(-3y-12)/2

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solvefor x,3y-2x+12=0

solve for

x, 3 y - 2 x + 12 = 0

x = - \frac{- 3 y - 12}{2}

Solution steps

3 y - 2 x + 12 = 0

Move

3 y

to the right side

- 2 x + 12 = - 3 y

Move

12

to the right side

- 2 x = - 3 y - 12

Divide both sides by

- 2

x = - \frac{- 3 y - 12}{2}

r = \frac{( 2 ^{n + 4} + 2 ( 2 ^{n} ) )}{3 ( 2 ^{n} )}

- 9 y - 8 + 3 y + 7 = - 7 y + 8 y - 5 y + 9

2 x + 10 = 24

x, 2 x + 5 y - z = 30

2 n^{2} + 3 n - 2 \cdot (n - 1)^{2} - 3 (n - 1) = 4 n + 1

What is the answer to solvefor x,3y-2x+12=0 ?
The answer to solvefor x,3y-2x+12=0 is x=-(-3y-12)/2