What are the solutions to the equation -2/3 x^2-1=17 ?

The solutions to the equation -2/3 x^2-1=17 are x=3sqrt(3)i,x=-3sqrt(3)i

Find the zeros of -2/3 x^2-1=17

The zeros of -2/3 x^2-1=17 are x=3sqrt(3)i,x=-3sqrt(3)i

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- \frac{2}{3} x^{2} - 1 = 17

x = 33 i, x = - 33 i

Solution steps

- \frac{2}{3} x^{2} - 1 = 17

Move

1

to the right side

- \frac{2}{3} x^{2} = 18

Multiply both sides by

3

- 2 x^{2} = 54

Divide both sides by

- 2

x^{2} = - 27

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 27, x = - - 27

- 27 = 33 i

- - 27 = - 33 i

x = 33 i, x = - 33 i

s^{2} - 5 s + 4 = 0

18 y^{3} - 50 y

\frac{3 x + 6}{x ( x - 4 )} \leq 0

m^{2} + 5 m

6 = \frac{1}{3} x + 5

What are the solutions to the equation -2/3 x^2-1=17 ?
The solutions to the equation -2/3 x^2-1=17 are x=3sqrt(3)i,x=-3sqrt(3)i
Find the zeros of -2/3 x^2-1=17
The zeros of -2/3 x^2-1=17 are x=3sqrt(3)i,x=-3sqrt(3)i