What is the answer to solvefor x,((2n+3))/((n+2))=x+y/((n-2)) ?

The answer to solvefor x,((2n+3))/((n+2))=x+y/((n-2)) is x=(2n+3)/(n+2)-y/(n-2)

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solvefor x,((2n+3))/((n+2))=x+y/((n-2))

solve for

x, \frac{( 2 n + 3 )}{( n + 2 )} = x + \frac{y}{( n - 2 )}

x = \frac{2 n + 3}{n + 2} - \frac{y}{n - 2}

Solution steps

\frac{( 2 n + 3 )}{( n + 2 )} = x + \frac{y}{( n - 2 )}

Switch sides

x + \frac{y}{n - 2} = \frac{2 n + 3}{n + 2}

x + \frac{y}{n - 2} = \frac{2 n + 3}{n + 2}

Move

\frac{y}{n - 2}

to the right side

x = \frac{2 n + 3}{n + 2} - \frac{y}{n - 2}

x \cdot (1.07)^{10} = 1000000

\frac{2 x \cdot 81}{5} = \frac{21}{5}

c, c (t) = 5^{6} \cdot (1 + 4 e^{- 2 t})^{- 1}

x, 15 (x - y) - 3 (x - 9) + 5 (x + 6) = 0

x, y = f (x + 1) - 4

What is the answer to solvefor x,((2n+3))/((n+2))=x+y/((n-2)) ?
The answer to solvefor x,((2n+3))/((n+2))=x+y/((n-2)) is x=(2n+3)/(n+2)-y/(n-2)