What is the answer to solvefor a,c=h*((a+b))/2 ?

The answer to solvefor a,c=h*((a+b))/2 is a=(2c-hb)/h ;\quad h\ne 0

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solvefor a,c=h*((a+b))/2

solve for

a, c = h \cdot \frac{( a + b )}{2}

a = \frac{2 c - hb}{h}; h \neq = 0

Solution steps

c = h \frac{( a + b )}{2}

Switch sides

h \frac{a + b}{2} = c

Expand

h \frac{a + b}{2} : \frac{ah}{2} + \frac{hb}{2}

\frac{ah}{2} + \frac{hb}{2} = c

Multiply both sides by

2

ah + hb = 2 c

Move

hb

to the right side

ah = 2 c - hb

Divide both sides by

h; h \neq = 0

a = \frac{2 c - hb}{h}; h \neq = 0

\frac{( 3 x - 1 )}{3 + 75} = \frac{( x + 1 )}{3}

(x + 2) (x + 3) (x - 1) = (x + 4) (x + 4) (x - 4) - 27

0.32 x = 3

415 + (164 - x) = 501

x, - 3 x - 9 y = 0

What is the answer to solvefor a,c=h*((a+b))/2 ?
The answer to solvefor a,c=h*((a+b))/2 is a=(2c-hb)/h ;\quad h\ne 0