What is the answer to solvefor x,2xy=1+y^2 ?

The answer to solvefor x,2xy=1+y^2 is x=(1+y^2)/(2y);\quad y\ne 0

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solvefor x,2xy=1+y^2

solve for

x, 2 x y = 1 + y^{2}

x = \frac{1 + y ^{2}}{2 y}; y \neq = 0

Solution steps

2 x y = 1 + y^{2}

Divide both sides by

2 y; y \neq = 0

x = \frac{1 + y ^{2}}{2 y}; y \neq = 0

h, 3 h = 7 (\frac{2}{7} - \frac{3}{7} \cdot n) - 10

x, p^{2} + p (2 x - y) - 2 x y = 0

x, x - 7 = 7 y

\frac{4 u - 7}{- 7} = \frac{u - 4}{4}

x, y^{0.12} = 6 x + 3 y

What is the answer to solvefor x,2xy=1+y^2 ?
The answer to solvefor x,2xy=1+y^2 is x=(1+y^2)/(2y);\quad y\ne 0