What are the solutions to the equation 2(x+3)^2=32 ?

The solutions to the equation 2(x+3)^2=32 are x=1,x=-7

Find the zeros of 2(x+3)^2=32

The zeros of 2(x+3)^2=32 are x=1,x=-7

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2 (x + 3)^{2} = 32

x = 1, x = - 7

Solution steps

2 (x + 3)^{2} = 32

Divide both sides by

2

(x + 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 16 : x = 1

Solve

x + 3 = - 16 : x = - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

4 x^{2} + 38 x + 70

2 x^{2} + x = 6

3 x^{3} + 5 x^{2} - 4 x - 4

x + 3 < 0 or 3 x > - 6

- 1 + \frac{x}{2} = 9

What are the solutions to the equation 2(x+3)^2=32 ?
The solutions to the equation 2(x+3)^2=32 are x=1,x=-7
Find the zeros of 2(x+3)^2=32
The zeros of 2(x+3)^2=32 are x=1,x=-7