What is the answer to x+((x+5)/2)+((x+41)/4)= 483/4 ?

The answer to x+((x+5)/2)+((x+41)/4)= 483/4 is x= 432/7

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x+((x+5)/2)+((x+41)/4)= 483/4

x + (\frac{x + 5}{2}) + (\frac{x + 41}{4}) = \frac{483}{4}

x = \frac{432}{7}

Decimal Notation

x = 61.71428 \dots

Solution steps

x + (\frac{x + 5}{2}) + (\frac{x + 41}{4}) = \frac{483}{4}

Expand

x + (\frac{x + 5}{2}) + (\frac{x + 41}{4}) : \frac{7 x}{4} + \frac{51}{4}

\frac{7 x}{4} + \frac{51}{4} = \frac{483}{4}

Multiply both sides by

4

7 x + 51 = 483

Move

51

to the right side

7 x = 432

Divide both sides by

7

x = \frac{432}{7}

y, \frac{( d ^{2} \cdot y )}{( d \cdot x ^{2} )} = e^{5 x}

4242 = 2200 (\frac{1 + 0.017}{12})^{12} t

x, (y - x) p + (2 - x) y = x - y

y, x = lo g_{3} (lo g_{2} (512)) \cdot y

3 x + 2 (x - 3) = 4 (2 + x)

What is the answer to x+((x+5)/2)+((x+41)/4)= 483/4 ?
The answer to x+((x+5)/2)+((x+41)/4)= 483/4 is x= 432/7
Solve for x: x+((x+5)/2)+((x+41)/4)= 483/4
The solution is x= 432/7