What is the answer to solvefor x,y^1= 1/(e^{-y)}-x ?

The answer to solvefor x,y^1= 1/(e^{-y)}-x is x=e^y-y

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solvefor x,y^1= 1/(e^{-y)}-x

solve for

x, y^{1} = \frac{1}{e ^{- y}} - x

x = e^{y} - y

Solution steps

y^{1} = \frac{1}{e ^{- y}} - x

Move

x

to the left side

y + x = \frac{1}{e ^{- y}}

Simplify

\frac{1}{e ^{- y}} : e^{y}

y + x = e^{y}

Move

y

to the right side

x = e^{y} - y

8 a + 3 (2 - 1.5 a) = 30 - a

(- 4 + 8 a) \cdot x - 14 a - 7 = 0

x, y - 4 = - 1 (x - (- 4))

x, 3 x - 2 (x + y) = 3

x, 3 x + 3 y - z + 2 t = - 1

What is the answer to solvefor x,y^1= 1/(e^{-y)}-x ?
The answer to solvefor x,y^1= 1/(e^{-y)}-x is x=e^y-y