What is the answer to solvefor x,3x+3y-z+2t=-1 ?

The answer to solvefor x,3x+3y-z+2t=-1 is x=(-1-3y+z-2t)/3

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solvefor x,3x+3y-z+2t=-1

solve for

x, 3 x + 3 y - z + 2 t = - 1

x = \frac{- 1 - 3 y + z - 2 t}{3}

Solution steps

3 x + 3 y - z + 2 t = - 1

Move

3 y

to the right side

3 x - z + 2 t = - 1 - 3 y

Move

z

to the right side

3 x + 2 t = - 1 - 3 y + z

Move

2 t

to the right side

3 x = - 1 - 3 y + z - 2 t

Divide both sides by

3

x = \frac{- 1 - 3 y + z - 2 t}{3}

\frac{1}{( 3 )} = \frac{h}{15}

x \cdot 27 + 21 = \frac{( 6 x )}{( 3 )}

[(x - 1)^{2} - (x + 1)^{2}]^{2} = (4 x - 3)^{2}

x, 3 x + 5 y = 40 5^{2}

17 x - 5 = 2 x

What is the answer to solvefor x,3x+3y-z+2t=-1 ?
The answer to solvefor x,3x+3y-z+2t=-1 is x=(-1-3y+z-2t)/3