What is 28p^2(q^4)/(\frac{4pq^4){5r}} ?

The solution to 28p^2(q^4)/(\frac{4pq^4){5r}} is 35pr

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simplify 28p^2(q^4)/(\frac{4pq^4){5r}}

simplify

28 p^{2} \frac{q ^{4}}{\frac{4 p q ^{4}}{5 r}}

35 p r

Solution steps

28 p^{2} \frac{q ^{4}}{\frac{4 p q ^{4}}{5 r}}

Simplify

\frac{q ^{4}}{\frac{4 p q ^{4}}{5 r}} : \frac{5 r}{4 p}

= 28 p^{2} \frac{5 r}{4 p}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{28 p ^{2} \cdot 5 r}{4 p}

Factor the number:

28 = 4 \cdot 7

= \frac{4 \cdot 7 p ^{2} \cdot 5 r}{4 p}

Cancel the common factor:

4

= \frac{7 p ^{2} \cdot 5 r}{p}

Simplify

\frac{p ^{2}}{p} : p

= 7 p \cdot 5 r

Multiply the numbers:

7 \cdot 5 = 35

= 35 p r

3^{n + 1} + 3^{n} - 12 \cdot 3^{n - 1}

9 (x + 10) = - 63

x^{3} - x^{2} \geq 0

x^{2} + (\frac{1}{9} x^{2} - 20 x + 900) = 1620

9 x^{2} - 26 x - 3

What is 28p^2(q^4)/(\frac{4pq^4){5r}} ?
The solution to 28p^2(q^4)/(\frac{4pq^4){5r}} is 35pr