What is the answer to log_{10}(0.4)(8+2x)=1 ?

The answer to log_{10}(0.4)(8+2x)=1 is x=(1-8log_{10}(0.4))/(2log_{10)(0.4)}

Solve for x: log_{10}(0.4)(8+2x)=1

The solution is x=(1-8log_{10}(0.4))/(2log_{10)(0.4)}

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lo g_{10} (0.4) (8 + 2 x) = 1

x = \frac{1 - 8 lo g _{10} ( 0.4 )}{2 lo g _{10} ( 0.4 )}

Decimal Notation

x = - 5.25647 \dots

Solution steps

lo g_{10} (0.4) (8 + 2 x) = 1

Divide both sides by

lo g_{10} (0.4)

8 + 2 x = \frac{1}{lo g _{10} ( 0.4 )}

Move

8

to the right side

2 x = \frac{1}{lo g _{10} ( 0.4 )} - 8

Divide both sides by

2

x = \frac{1 - 8 lo g _{10} ( 0.4 )}{2 lo g _{10} ( 0.4 )}

- 1 = \frac{6 + x}{2}

\frac{a ( 2 x )}{7} = \frac{6}{3}

x, 2 x + y = 48

(a^{2} - 9) \cdot x = a^{3} + 27

v = 3 \cdot 9.8

What is the answer to log_{10}(0.4)(8+2x)=1 ?
The answer to log_{10}(0.4)(8+2x)=1 is x=(1-8log_{10}(0.4))/(2log_{10)(0.4)}
Solve for x: log_{10}(0.4)(8+2x)=1
The solution is x=(1-8log_{10}(0.4))/(2log_{10)(0.4)}