What are the solutions to the equation 16x^2-24x-91=0 ?

The solutions to the equation 16x^2-24x-91=0 are x= 13/4 ,x=-7/4

Find the zeros of 16x^2-24x-91=0

The zeros of 16x^2-24x-91=0 are x= 13/4 ,x=-7/4

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16 x^{2} - 24 x - 91 = 0

x = \frac{13}{4}, x = - \frac{7}{4}

Solution steps

16 x^{2} - 24 x - 91 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 ( - 91 )}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 (- 91) = 80

x_{1, 2} = \frac{- ( - 24 ) \pm 80}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 80}{2 \cdot 16}, x_{2} = \frac{- ( - 24 ) - 80}{2 \cdot 16}

x = \frac{- ( - 24 ) + 80}{2 \cdot 16} : \frac{13}{4}

x = \frac{- ( - 24 ) - 80}{2 \cdot 16} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{13}{4}, x = - \frac{7}{4}

4 - (9 h - 4) < 8 h - 8 + 7

\frac{2}{3} - \frac{1}{6} - 3

10 x^{2} + 20 x - 80

9 - x^{2} + 2 x y - y^{2}

∣ 2 x - 1 ∣ \geq 5

What are the solutions to the equation 16x^2-24x-91=0 ?
The solutions to the equation 16x^2-24x-91=0 are x= 13/4 ,x=-7/4
Find the zeros of 16x^2-24x-91=0
The zeros of 16x^2-24x-91=0 are x= 13/4 ,x=-7/4