What is the answer to (1+2i)z-3i+4i=2(z+3) ?

The answer to (1+2i)z-3i+4i=2(z+3) is z=-8/5-i 11/5

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(1+2i)z-3i+4i=2(z+3)

(1 + 2 i) z - 3 i + 4 i = 2 (z + 3)

z = - \frac{8}{5} - i \frac{11}{5}

Solution steps

(1 + 2 i) z - 3 i + 4 i = 2 (z + 3)

Add similar elements:

- 3 i + 4 i = i

(1 + 2 i) z + i = 2 (z + 3)

Expand

z (1 + 2 i) : z + 2 i z

z + 2 i z + i = 2 (z + 3)

Expand

2 (z + 3) : 2 z + 6

z + 2 i z + i = 2 z + 6

Move

i

to the right side

z + 2 i z = 2 z + 6 - i

Move

2 z

to the left side

2 i z - z = 6 - i

Factor

2 i z - z : (2 i - 1) z

(2 i - 1) z = 6 - i

Divide both sides by

2 i - 1

z = - \frac{8}{5} - i \frac{11}{5}

\frac{8}{5} = - 4 u

7 \cdot i = 7 \cdot x

j, j (x) = x^{4} - 3 x^{2} - 4

0.75 (4 f - 3) = 0.05 (20 f - 9)

\frac{4 x - 2 x}{9 + 7} = \frac{5 - 4 x}{2}

What is the answer to (1+2i)z-3i+4i=2(z+3) ?
The answer to (1+2i)z-3i+4i=2(z+3) is z=-8/5-i 11/5