What is the answer to solvefor j,j(x)=x^4-3x^2-4 ?

The answer to solvefor j,j(x)=x^4-3x^2-4 is j=(x^4-3x^2-4)/x ;\quad x\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor j,j(x)=x^4-3x^2-4

solve for

j, j (x) = x^{4} - 3 x^{2} - 4

j = \frac{x ^{4} - 3 x ^{2} - 4}{x}; x \neq = 0

Solution steps

j (x) = x^{4} - 3 x^{2} - 4

Divide both sides by

x; x \neq = 0

j = \frac{x ^{4} - 3 x ^{2} - 4}{x}; x \neq = 0

0.75 (4 f - 3) = 0.05 (20 f - 9)

\frac{4 x - 2 x}{9 + 7} = \frac{5 - 4 x}{2}

x, 2 y = - x + 4

f, z = (x + y) f (x^{2} y^{2})

x, 3 z - 2 x + 6 = 0

What is the answer to solvefor j,j(x)=x^4-3x^2-4 ?
The answer to solvefor j,j(x)=x^4-3x^2-4 is j=(x^4-3x^2-4)/x ;\quad x\ne 0