What are the solutions to the equation 3x^2+11x-4=0 ?

The solutions to the equation 3x^2+11x-4=0 are x= 1/3 ,x=-4

Find the zeros of 3x^2+11x-4=0

The zeros of 3x^2+11x-4=0 are x= 1/3 ,x=-4

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3 x^{2} + 11 x - 4 = 0

x = \frac{1}{3}, x = - 4

Decimal Notation

x = 0.33333 \dots, x = - 4

Solution steps

3 x^{2} + 11 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 (- 4) = 13

x_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 11 + 13}{2 \cdot 3}, x_{2} = \frac{- 11 - 13}{2 \cdot 3}

x = \frac{- 11 + 13}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 11 - 13}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 4

∣ x + 4 ∣ = ∣ 2 x + 1 ∣

3 x^{2} + 9 x

\frac{z}{5} - 1 \leq 1

(5 x - 2) (- x + 3) = 0

2 x - 1 \leq x

What are the solutions to the equation 3x^2+11x-4=0 ?
The solutions to the equation 3x^2+11x-4=0 are x= 1/3 ,x=-4
Find the zeros of 3x^2+11x-4=0
The zeros of 3x^2+11x-4=0 are x= 1/3 ,x=-4