What is the answer to solvefor f,(i)f=2x^3+x^2+x+4 ?

The answer to solvefor f,(i)f=2x^3+x^2+x+4 is f=i(-4-x-x^2-2x^3)

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solvefor f,(i)f=2x^3+x^2+x+4

solve for

f, (i) f = 2 x^{3} + x^{2} + x + 4

f = i (- 4 - x - x^{2} - 2 x^{3})

Solution steps

(i) f = 2 x^{3} + x^{2} + x + 4

Divide both sides by

i

f = i (- 4 - x - x^{2} - 2 x^{3})

2^{2} - x = \frac{1}{8}

x, y (n) = x (n) + x (n - 1)

x, x m o d = 5

\frac{( 4 + x )}{7} - \frac{( x + 6 )}{3} = - 1

3 x + 2 = 27

What is the answer to solvefor f,(i)f=2x^3+x^2+x+4 ?
The answer to solvefor f,(i)f=2x^3+x^2+x+4 is f=i(-4-x-x^2-2x^3)