What is the answer to (a-2020)x+2022=b ?

The answer to (a-2020)x+2022=b is x=(b-2022)/(a-2020);\quad a\ne 2020

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(a-2020)x+2022=b

(a - 2020) x + 2022 = b

x = \frac{b - 2022}{a - 2020}; a \neq = 2020

Solution steps

(a - 2020) x + 2022 = b

Move

2022

to the right side

(a - 2020) x = b - 2022

Divide both sides by

a - 2020; a \neq = 2020

x = \frac{b - 2022}{a - 2020}; a \neq = 2020

12 - 2 i = 3 k - 2 i

k = \frac{( 2 f ( - 2 ) - 4 f ( f ( - 3 ) ) )}{( f ( - 1 ) - 3 )}

\frac{1}{( lo g _{6} ( 12 ) )} + \frac{1}{( lo g _{2} ( 12 ) )} = x

x, 2 (8 x - 5 y) = 34

x, 141 x + 93 y = 189

What is the answer to (a-2020)x+2022=b ?
The answer to (a-2020)x+2022=b is x=(b-2022)/(a-2020);\quad a\ne 2020