What is the answer to solvefor k,x^3+k*x^2-4x+12=x+2 ?

The answer to solvefor k,x^3+k*x^2-4x+12=x+2 is k=(-x^3+5x-10)/(x^2);\quad x\ne 0

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solvefor k,x^3+k*x^2-4x+12=x+2

solve for

k, x^{3} + k \cdot x^{2} - 4 x + 12 = x + 2

k = \frac{- x ^{3} + 5 x - 10}{x ^{2}}; x \neq = 0

Solution steps

x^{3} + k x^{2} - 4 x + 12 = x + 2

Move

x^{3}

to the right side

k x^{2} - 4 x + 12 = x + 2 - x^{3}

Move

4 x

to the right side

k x^{2} + 12 = - x^{3} + 5 x + 2

Move

12

to the right side

k x^{2} = - x^{3} + 5 x - 10

Divide both sides by

x^{2}; x \neq = 0

k = \frac{- x ^{3} + 5 x - 10}{x ^{2}}; x \neq = 0

5 (2 x) - 6.5 (x) + 5 = 0

p, p (- 1) = 12 y^{3} - 39 y^{2} + 50 y + 97

(a^{2} - 9) x = a^{3} + 27

m, m + 5 n = 0

x = \frac{( - a )}{4} + \frac{2}{3} \cdot b

What is the answer to solvefor k,x^3+k*x^2-4x+12=x+2 ?
The answer to solvefor k,x^3+k*x^2-4x+12=x+2 is k=(-x^3+5x-10)/(x^2);\quad x\ne 0