What is the answer to d=sqrt((3/(4-0))^2+(0-4)^2) ?

The answer to d=sqrt((3/(4-0))^2+(0-4)^2) is d=(sqrt(265))/4

Solve for d: d=sqrt((3/(4-0))^2+(0-4)^2)

The solution is d=(sqrt(265))/4

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d = (\frac{3}{4 - 0})^{2} + (0 - 4)^{2}

d = \frac{265}{4}

Decimal Notation

d = 4.06970 \dots

Solution steps

d = (\frac{3}{4 - 0})^{2} + (0 - 4)^{2}

Simplify

(\frac{3}{4 - 0})^{2} + (0 - 4)^{2} : \frac{265}{4}

d = \frac{265}{4}

r = 8^{2} + 6^{2} + 2 (8) (1)

x, sin (y) = 1 - tan (x)

12 + x = 0

x, \frac{( x + 2 y )}{0.5} z = 128

2 \frac{x}{3} = - 10

What is the answer to d=sqrt((3/(4-0))^2+(0-4)^2) ?
The answer to d=sqrt((3/(4-0))^2+(0-4)^2) is d=(sqrt(265))/4
Solve for d: d=sqrt((3/(4-0))^2+(0-4)^2)
The solution is d=(sqrt(265))/4