What is the answer to solvefor y,(d^3-4d^2+5d)y-2=0 ?

The answer to solvefor y,(d^3-4d^2+5d)y-2=0 is y= 2/(d^3-4d^2+5d);\quad d\ne 0,d\ne 2+i,d\ne 2-i

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solvefor y,(d^3-4d^2+5d)y-2=0

solve for

y, (d^{3} - 4 d^{2} + 5 d) y - 2 = 0

y = \frac{2}{d ^{3} - 4 d ^{2} + 5 d}; d \neq = 0, d \neq = 2 + i, d \neq = 2 - i

Solution steps

(d^{3} - 4 d^{2} + 5 d) y - 2 = 0

Move

2

to the right side

(d^{3} - 4 d^{2} + 5 d) y = 2

Divide both sides by

d^{3} - 4 d^{2} + 5 d; d \neq = 0, d \neq = 2 + i, d \neq = 2 - i

y = \frac{2}{d ^{3} - 4 d ^{2} + 5 d}; d \neq = 0, d \neq = 2 + i, d \neq = 2 - i

x, (3 x + y) = (3 x - y)

x, - 2 x - 3 y = 1

a, a - a - 2 d - a - 1 d = 23

b = \frac{( \frac{3}{20} + \frac{1}{2} + \frac{1}{15} )}{( \frac{31}{3} + \frac{2}{9} )}

x, 5 x + 6 y = 17.25

What is the answer to solvefor y,(d^3-4d^2+5d)y-2=0 ?
The answer to solvefor y,(d^3-4d^2+5d)y-2=0 is y= 2/(d^3-4d^2+5d);\quad d\ne 0,d\ne 2+i,d\ne 2-i