What is the answer to solvefor x,(x+y)^2=x^2+4y^2+2x*y ?

The answer to solvefor x,(x+y)^2=x^2+4y^2+2x*y is True for all x;\quad 0=3y^2

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solvefor x,(x+y)^2=x^2+4y^2+2x*y

solve for

x, (x + y)^{2} = x^{2} + 4 y^{2} + 2 x \cdot y

True for all x; 0 = 3 y^{2}

Solution steps

(x + y)^{2} = x^{2} + 4 y^{2} + 2 x y

Expand

(x + y)^{2} : x^{2} + 2 x y + y^{2}

x^{2} + 2 x y + y^{2} = x^{2} + 4 y^{2} + 2 x y

Move

y^{2}

to the right side

x^{2} + 2 x y = 3 y^{2} + 2 x y + x^{2}

Subtract

2 x y + x^{2}

from both sides

x^{2} + 2 x y - (2 x y + x^{2}) = 3 y^{2} + 2 x y + x^{2} - (2 x y + x^{2})

Simplify

0 = 3 y^{2}

Both sides are equal

True for all x; 0 = 3 y^{2}

7 + 0.23 x = 30

\frac{c + 4}{2} = \frac{2.5 - 9}{3}

m = (x + 6)^{2} + (x - 4)^{2} - 2 x^{2}

x, 7 x - (- 2 y) = 47

0.75 (8 b + 4) - 1 = 4 b + 140

What is the answer to solvefor x,(x+y)^2=x^2+4y^2+2x*y ?
The answer to solvefor x,(x+y)^2=x^2+4y^2+2x*y is True for all x;\quad 0=3y^2