What is the answer to 0.12x+0.2(x-4)=0.01(3x-2) ?

The answer to 0.12x+0.2(x-4)=0.01(3x-2) is x= 78/29

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0.12x+0.2(x-4)=0.01(3x-2)

0.12 x + 0.2 (x - 4) = 0.01 (3 x - 2)

x = \frac{78}{29}

Decimal Notation

x = 2.68965 \dots

Solution steps

0.12 x + 0.2 (x - 4) = 0.01 (3 x - 2)

Multiply both sides by

100

12 x + 20 (x - 4) = 3 x - 2

Expand

20 (x - 4) : 20 x - 80

12 x + 20 x - 80 = 3 x - 2

Add similar elements:

12 x + 20 x = 32 x

32 x - 80 = 3 x - 2

Move

80

to the right side

32 x = 3 x + 78

Move

3 x

to the left side

29 x = 78

Divide both sides by

29

x = \frac{78}{29}

4 x + 9 = 3 x - 7

(\frac{- 1}{3})^{3} x = \frac{1}{81}

8 x - 2 x + 2 = 7

a = 0.17 5^{\cdot} h d

y, a = t^{4} - 5 t^{2} + 8 t - 5 y

What is the answer to 0.12x+0.2(x-4)=0.01(3x-2) ?
The answer to 0.12x+0.2(x-4)=0.01(3x-2) is x= 78/29
Solve for x: 0.12x+0.2(x-4)=0.01(3x-2)
The solution is x= 78/29