What is the answer to (x+1)(x+2)(x+5)-x^2(x+8)=27 ?

The answer to (x+1)(x+2)(x+5)-x^2(x+8)=27 is x=1

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(x+1)(x+2)(x+5)-x^2(x+8)=27

(x + 1) (x + 2) (x + 5) - x^{2} (x + 8) = 27

x = 1

Solution steps

(x + 1) (x + 2) (x + 5) - x^{2} (x + 8) = 27

Expand

(x + 1) (x + 2) (x + 5) - x^{2} (x + 8) : 17 x + 10

17 x + 10 = 27

Move

10

to the right side

17 x = 17

Divide both sides by

17

x = 1

z, p^{2} + q^{2} = z + 3

f = 1 - e^{- (\frac{0.693}{700}) \cdot (4 \cdot 1 0^{- 3})}

x, f = e sin (a) f (6) (x)

(x + 4)^{2} - (x - 5)^{2} = 9

x, f^{26} (x) = f^{11} (x) + f^{12} (x)

What is the answer to (x+1)(x+2)(x+5)-x^2(x+8)=27 ?
The answer to (x+1)(x+2)(x+5)-x^2(x+8)=27 is x=1
Solve for x: (x+1)(x+2)(x+5)-x^2(x+8)=27
The solution is x=1