What is the answer to solvefor x,f^{26}(x)=f^{11}(x)+f^{12}(x) ?

The answer to solvefor x,f^{26}(x)=f^{11}(x)+f^{12}(x) is x=0

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solvefor x,f^{26}(x)=f^{11}(x)+f^{12}(x)

solve for

x, f^{26} (x) = f^{11} (x) + f^{12} (x)

x = 0

Solution steps

f^{26} (x) = f^{11} (x) + f^{12} (x)

f^{26} x = x f^{11} + x f^{12}

Expand

f^{26} (x) : x f^{26}

x f^{26} = x f^{11} + x f^{12}

Subtract

x f^{11} + x f^{12}

from both sides

x f^{26} - (x f^{11} + x f^{12}) = x f^{11} + x f^{12} - (x f^{11} + x f^{12})

Simplify

x f^{26} - x f^{11} - x f^{12} = 0

Factor

x f^{26} - x f^{11} - x f^{12} : x f^{11} (f^{15} - 1 - f)

x f^{11} (f^{15} - 1 - f) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0

9 m + 3 = 2 (m - 1) + 5 z

(b) 8 \cdot 2^{n + 2} = 32

x, p (x y) = 2 \cdot 2 + y^{2} - x y - 2 x y

3 + a = 2 a

y, (x + 1) (y - 1) - 2 e^{- 2 x} + 1 = 0

What is the answer to solvefor x,f^{26}(x)=f^{11}(x)+f^{12}(x) ?
The answer to solvefor x,f^{26}(x)=f^{11}(x)+f^{12}(x) is x=0