What is the answer to solvefor m,-5=m(0)n(-1/2)+nm+n ?

The answer to solvefor m,-5=m(0)n(-1/2)+nm+n is m=(-5-n)/n ;\quad n\ne 0

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solvefor m,-5=m(0)n(-1/2)+nm+n

solve for

m, - 5 = m (0) n (- \frac{1}{2}) + nm + n

m = \frac{- 5 - n}{n}; n \neq = 0

Solution steps

- 5 = m (0) n (- \frac{1}{2}) + nm + n

Switch sides

m 0 n (- \frac{1}{2}) + nm + n = - 5

Remove parentheses:

(a) = a

- m \cdot 0 \cdot n \frac{1}{2} + nm + n = - 5

Apply rule

0 \cdot a = 0

- 0 + mn + n = - 5

- 0 + nm + n = nm + n

mn + n = - 5

Move

n

to the right side

mn = - 5 - n

Divide both sides by

n; n \neq = 0

m = \frac{- 5 - n}{n}; n \neq = 0

t, s = \frac{( v + v )}{2} \cdot t

4 n - 18 = 151 - 5 n

x, 7 x + 3 y = 6

- 3 x + 2 = - x - 5

f, f 0. 9^{n + 1} - 9^{n} = 72

What is the answer to solvefor m,-5=m(0)n(-1/2)+nm+n ?
The answer to solvefor m,-5=m(0)n(-1/2)+nm+n is m=(-5-n)/n ;\quad n\ne 0