What is the answer to (3^2x+3)/(9^3)=9^{14} ?

The answer to (3^2x+3)/(9^3)=9^{14} is x=(9^{17}-3)/9

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(3^2x+3)/(9^3)=9^{14}

\frac{3 ^{2} x + 3}{9 ^{3}} = 9^{14}

x = \frac{9 ^{17} - 3}{9}

Decimal Notation

x = 1.85302 E 15

Solution steps

\frac{3 ^{2} x + 3}{9 ^{3}} = 9^{14}

Multiply both sides by

9^{3}

3^{2} x + 3 = 9^{17}

Move

3

to the right side

3^{2} x = 9^{17} - 3

Divide both sides by

9

x = \frac{9 ^{17} - 3}{9}

x, \frac{111}{11} x - \frac{301}{13} y = 0

x, 0.2 x + 0.8 y = 9.1

x, x + 13 = 12 y

2 m = \frac{( 8 ) ^{\frac{1}{3}}}{( ( 2 ^{3} ) ^{\frac{2}{3}} )}

x = \frac{13}{( 3 - 2 i )}, x^{4} - 4 x^{3} - 6 x^{2} - 4 x + 7^{2}

What is the answer to (3^2x+3)/(9^3)=9^{14} ?
The answer to (3^2x+3)/(9^3)=9^{14} is x=(9^{17}-3)/9
Solve for x: (3^2x+3)/(9^3)=9^{14}
The solution is x=(9^{17}-3)/9