What is the answer to c^{0.9}x-3(x+8)=8x+2 ?

The answer to c^{0.9}x-3(x+8)=8x+2 is x=(26)/(c^{0.9)-11};\quad c\ne 11\sqrt[9]{11}

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c^{0.9}x-3(x+8)=8x+2

c^{0.9} x - 3 (x + 8) = 8 x + 2

Solution steps

c^{0.9} x - 3 (x + 8) = 8 x + 2

Expand

- 3 (x + 8) : - 3 x - 24

c^{0.9} x - 3 x - 24 = 8 x + 2

Move

24

to the right side

c^{0.9} x - 3 x = 8 x + 26

Move

8 x

to the left side

c^{0.9} x - 11 x = 26

Factor

c^{0.9} x - 11 x : x (c^{0.9} - 11)

x (c^{0.9} - 11) = 26

Divide both sides by

\frac{1}{3} = - 2

lo g_{10} (10) (x) + lo g_{10} (10) (2 x + 1) = 1

987 - (x + 14) = 678

n = \frac{1}{1.6} \cdot 1 0^{19}

\frac{( 3 x - 1 )}{15} + 2 + \frac{( x - 4 )}{5} = \frac{( x + 4 )}{3}

What is the answer to c^{0.9}x-3(x+8)=8x+2 ?
The answer to c^{0.9}x-3(x+8)=8x+2 is x=(26)/(c^{0.9)-11};\quad c\ne 11\sqrt[9]{11}