What is the answer to ((3x-1)}{15}+2+\frac{(x-4))/5 =((x+4))/3 ?

The answer to ((3x-1)}{15}+2+\frac{(x-4))/5 =((x+4))/3 is x=3

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((3x-1)}{15}+2+\frac{(x-4))/5 =((x+4))/3

\frac{( 3 x - 1 )}{15} + 2 + \frac{( x - 4 )}{5} = \frac{( x + 4 )}{3}

x = 3

Solution steps

\frac{( 3 x - 1 )}{15} + 2 + \frac{( x - 4 )}{5} = \frac{( x + 4 )}{3}

\frac{3 x - 1}{15} + 2 + \frac{x - 4}{5} = \frac{( x + 4 )}{3}

Multiply by LCM

3 x - 1 + 30 + 3 (x - 4) = 5 (x + 4)

Expand

3 x - 1 + 30 + 3 (x - 4) : 6 x + 17

Expand

5 (x + 4) : 5 x + 20

6 x + 17 = 5 x + 20

Move

17

to the right side

6 x = 5 x + 3

Move

5 x

to the left side

x = 3

\frac{202}{3} + \frac{61}{2} - \frac{91}{9} = x + \frac{18}{25}

y, (3) y = (2 x + 1)^{3} \cdot (x^{2} - x + 1)^{2}

\frac{x + ( - 2 )}{5} = - 3.2

m \cdot x - 4 x = 3 (8 x - 12) + 15

x = 15 - 2

What is the answer to ((3x-1)}{15}+2+\frac{(x-4))/5 =((x+4))/3 ?
The answer to ((3x-1)}{15}+2+\frac{(x-4))/5 =((x+4))/3 is x=3
Solve for x: ((3x-1)}{15}+2+\frac{(x-4))/5 =((x+4))/3
The solution is x=3