What is the answer to solvefor y,(3)y=(2x+1)^3*(x^2-x+1)^2 ?

The answer to solvefor y,(3)y=(2x+1)^3*(x^2-x+1)^2 is y=((2x+1)^3(x^2-x+1)^2)/3

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solvefor y,(3)y=(2x+1)^3*(x^2-x+1)^2

solve for

y, (3) y = (2 x + 1)^{3} \cdot (x^{2} - x + 1)^{2}

y = \frac{( 2 x + 1 ) ^{3} ( x ^{2} - x + 1 ) ^{2}}{3}

Solution steps

(3) y = (2 x + 1)^{3} (x^{2} - x + 1)^{2}

Divide both sides by

3

y = \frac{( 2 x + 1 ) ^{3} ( x ^{2} - x + 1 ) ^{2}}{3}

\frac{x + ( - 2 )}{5} = - 3.2

m \cdot x - 4 x = 3 (8 x - 12) + 15

x = 15 - 2

5 (2 + x) - 9 = 200

\frac{1}{2} \cdot 1 - \frac{1}{4} = - 1, \frac{1}{x} \cdot \frac{1}{( 2 y )} = 8

What is the answer to solvefor y,(3)y=(2x+1)^3*(x^2-x+1)^2 ?
The answer to solvefor y,(3)y=(2x+1)^3*(x^2-x+1)^2 is y=((2x+1)^3(x^2-x+1)^2)/3